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Physics

The velocity of a moving cart is reduced to 13\dfrac{1}{3}rd the initial velocity. Its kinetic energy is reduced by :

  1. 12\dfrac{1}{2}

  2. 13\dfrac{1}{3}

  3. 16\dfrac{1}{6}

  4. 19\dfrac{1}{9}

Work, Energy & Power

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Answer

19\dfrac{1}{9}

Reason — Let initial velocity be v.

Kinetic Energy at v = 12\dfrac{1}{2} x m x v2 = mv22\dfrac{\text{mv}^2}{2}

Kinetic Energy at v3\dfrac{\text{v}}{3} = 12\dfrac{1}{2} x m x (v3)2(\dfrac{\text{v}}{3})^2 = 19(mv22)\dfrac{1}{9}\Big(\dfrac{\text{mv}^2}{2}\Big)

Hence, the kinetic energy is reduced by 19\dfrac{1}{9}

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