Find the value of θ (0° < θ < 90°) if :

tan 35° cot (90° - θ) = 1.

If A, B and C are the interior angles of a △ABC, show that :

(i) cos $\dfrac{A + B}{2}$ = sin $\dfrac{C}{2}$

(ii) tan $\dfrac{C + A}{2}$ = cot $\dfrac{B}{2}$

The value of (sin 45° + cos 45°) is

1. $\dfrac{1}{\sqrt{2}}$

2. $\sqrt{2}$

3. $\dfrac{\sqrt{3}}{2}$

4. 1

The value of tan² 30° - 4 sin² 45° is

1. 1

2. $\dfrac{7}{3}$

3. $-\dfrac{5}{3}$

4. $-\dfrac{11}{3}$