The value of 1sin 30°−3cos 30°\dfrac{1}{\text{sin 30°}} - \dfrac{\sqrt{3}}{\text{cos 30°}}sin 30°1−cos 30°3 is
2
1
12\dfrac{1}{2}21
0
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Solving,
⇒1sin 30°−3cos 30°=112−332=2−2=0.\Rightarrow \dfrac{1}{\text{sin 30°}} - \dfrac{\sqrt{3}}{\text{cos 30°}} = \dfrac{1}{\dfrac{1}{2}} - \dfrac{\sqrt{3}}{\dfrac{\sqrt{3}}{2}} \\[1em] = 2 - 2 \\[1em] = 0.⇒sin 30°1−cos 30°3=211−233=2−2=0.
Hence, Option 4 is the correct option.
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The value of (sin 30° + cos 30°) - (sin 60° + cos 60°) is
-1
The value of 3\sqrt{3}3 cosec 60° - sec 60° is
If tan A = 3\sqrt{3}3, then the value of cosec A is
23\dfrac{2}{\sqrt{3}}32
32\dfrac{\sqrt{3}}{2}23
If sec θ. sin θ = 0, then the value of cos θ is
12\dfrac{1}{\sqrt{2}}21
