Mathematics
The total surface area of a hollow cylinder, which is open from both the sides, is 3575 cm2; area of its base ring is 357.5 cm2 and its height is 14 cm. Find the thickness of the cylinder.
Mensuration
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Answer
Let external radius be R cm and internal radius be r cm.
Given,
Area of base of ring = 357.5 cm2
∴ π(R2 - r2) = 357.5
Given,
Total surface area of hollow cylinder = 3575 cm2.
Dividing (1) by (2), we get :
Hence, thickness of hollow cylinder = 3.5 cm.
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