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Physics

The time interval between a lightning flash and the first sound of thunder is 5 s. If the speed of sound in air is 330 m s-1 , find the distance of flash from the observer.

Sound Waves Propagation

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Answer

Given,

Time interval (t) = 5 s

Speed (V) = 330 m s-1

distance (d) = ?

V = Distance (d)Time (t)\dfrac{\text{Distance (d)}}{\text {Time (t)}}

Substituting the values, we get,

330=d5d=330×5d=1650 m330 = \dfrac{d}{5} \\[0.5em] \Rightarrow d = 330 \times 5 \\[0.5em] \Rightarrow d = 1650 \text { m} \\[0.5em]

Therefore, the distance of flash from the observer = 1650 m.

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