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The slope of the side BC of a rectangle ABCD is 23\dfrac{2}{3}. Find :

(i) the slope of the side AB,

(ii) the slope of the side AD.

Straight Line Eq

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Answer

Rectangle ABCD is shown in the figure below:

The slope of the side BC of a rectangle ABCD is 2/3. Find (i) the slope of the side AB, (ii) the slope of the side AD. Equation of a Line, Concise Mathematics Solutions ICSE Class 10.

Since, product of slope of perpendicular line = -1.

Slope of AB x Slope of BC = -1

Slope of AB×23=1Slope of AB=32.\Rightarrow \text{Slope of AB} \times \dfrac{2}{3} = -1 \\[1em] \Rightarrow \text{Slope of AB} = -\dfrac{3}{2}.

Hence, slope of AB = 32-\dfrac{3}{2}.

(ii) AD is parallel to BC and slope of parallel lines are equal.

Hence, slope of AD = 23\dfrac{2}{3}.

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