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Mathematics

The slope of a line perpendicular to the line passing through the points (2, 5) and (-3, 6) is

  1. 15-\dfrac{1}{5}

  2. 15\dfrac{1}{5}

  3. -5

  4. 5

Straight Line Eq

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Answer

Slope (m1) of line joining the points (2, 5) and (-3, 6) is given by

=y2y1x2x1=6532=15.= \dfrac{y2 - y1}{x_2 - x1} \\[1em] = \dfrac{6 - 5}{-3 - 2} \\[1em] = -\dfrac{1}{5}.

Let slope of perpendicular line be m2. Then,

m1×m2=115×m2=1m2=5.\Rightarrow m1 \times m2 = -1 \\[1em] \Rightarrow -\dfrac{1}{5} \times m2 = -1 \\[1em] \Rightarrow m2 = 5.

∴ Slope of line perpendicular to this line = 5.

Hence, Option 4 is the correct option.

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