The slope and the x-intercept of the line 5x - 5y = 12 are :

1. slope = 5 and x-intercept = $\dfrac{12}{5}$

2. slope = -1 and x-intercept = $\dfrac{12}{5}$

3. slope = 1 and x-intercept = $\dfrac{12}{5}$

4. slope = -5 and x-intercept = $\dfrac{12}{5}$

Given, equation :

⇒ 5x - 5y = 12

⇒ -5y = -5x + 12

⇒ 5y = 5x - 12

⇒ y = $\dfrac{5x}{5} - \dfrac{12}{5}$

⇒ y = x - $\dfrac{12}{5}$

Comparing above equation with y = mx + c (where m is slope and c is the y-intercept), we get :

⇒ m = 1 and c = $-\dfrac{12}{5}$

To find x-intercept of the line, we put y = 0 in above equation:

0 = x - $\dfrac{12}{5}$

⇒ x = $\dfrac{12}{5}$

∴ Slope = 1 and x-intercept = $\dfrac{12}{5}$

Hence, Option 3 is the correct option.