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The relative density of silver is 10.8. Find its density.

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Answer

We know,

R.D. = Density of substance in kg m31000 kg m3\dfrac{\text {Density of substance in kg m}^{-3}}{\text{1000 kg m}^{-3}}

Given,

relative density of silver = 10.8

Substituting the values in the formula above we get,

10.8=Density of silver1000 kg m3Density of silver=(10.8×1000)kg m310.8 = \dfrac{\text {Density of silver}}{\text{1000 kg m}^{-3}} \\[0.5em] \therefore \text {Density of silver} = (10.8 \times 1000) \text {kg m}^{-3}

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