Chemistry
The reaction of potassium permanganate with acidified iron (II) sulphate is given below :
2KMnO4 + 10FeSO4 + 8H2SO4 ⟶ K2SO4 + 2MnSO4 + 5 Fe2(SO4)3 + 8H2O.
If 15.8 g. of potassium permanganate was used in the reaction, calculate the mass of iron (II) sulphate used in the above reaction.
[K = 39, Mn = 55, Fe = 56, S = 32, O = 16]
Stoichiometry
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Answer
316 g of potassium permanganate was used with 1520 g of iron (II) sulphate
∴ 15.8 g. of potassium permanganate will be used with x 15.8 = 76 g of iron (II) sulphate
Hence, 76 g of iron (II) sulphate was used.
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