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Mathematics

The ratio in which the join of points (-2, 5) and (5, -2) is divided by y-axis is :

  1. 3 : 5

  2. 2 : 5

  3. 5 : 3

  4. 5 : 2

Section Formula

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Answer

Any point on y-axis can be defined as (0, y).

Let ratio in which the join of points (-2, 5) and (5, -2) is divided by (0, y) be k : 1.

(0,y)=(k×5+1×2k+1,k×2+1×5k+1)(0,y)=(5k2k+1,2k+5k+1)0=5k2k+15k2=05k=2k=25.\Rightarrow (0, y) = \Big(\dfrac{k \times 5 + 1 \times -2}{k + 1}, \dfrac{k \times -2 + 1 \times 5}{k + 1}\Big) \\[1em] \Rightarrow (0, y) = \Big(\dfrac{5k - 2}{k + 1}, \dfrac{-2k + 5}{k + 1}\Big) \\[1em] \Rightarrow 0 = \dfrac{5k - 2}{k + 1} \\[1em] \Rightarrow 5k - 2 = 0 \\[1em] \Rightarrow 5k = 2 \\[1em] \Rightarrow k = \dfrac{2}{5}.

Substituting value of k in k : 1, we get :

25:1\dfrac{2}{5} : 1

⇒ 2 : 5.

Hence, Option 2 is the correct option.

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