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Mathematics

The present population of a city is 12,00,000. If it increases at the rate of 8% every year then the population of the city after 2 years is

  1. 199680

  2. 1399680

  3. 1500000

  4. 1299680

Compound Interest

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Answer

By growth formula,

V=V0(1+r100)nV = V_0\Big(1 + \dfrac{r}{100}\Big)^n

Substituting values in formula,

V=1200000(1+8100)2=1200000(108100)2=1200000(108100)2=1200000(2725)2=1200000×2725×2725=1200000×729625=1920×729=1399680.V = 1200000\Big(1 + \dfrac{8}{100}\Big)^2 \\[1em] = 1200000\Big(\dfrac{108}{100}\Big)^2 \\[1em] = 1200000\Big(\dfrac{108}{100}\Big)^2 \\[1em] = 1200000\Big(\dfrac{27}{25}\Big)^2 \\[1em] = 1200000 \times \dfrac{27}{25} \times \dfrac{27}{25} \\[1em] = 1200000 \times \dfrac{729}{625} \\[1em] = 1920 \times 729 \\[1em] = 1399680.

Hence, Option 2 is the correct option.

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