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Mathematics

The points scored by a Kabaddi team in a series of matches are as follows:

7, 17, 2, 5, 27, 15, 8, 14, 10, 48, 10, 7, 24, 8, 28, 18.

Find the mean and the median of the points scored by the Kabaddi team.

Statistics

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Answer

Given,

Points scored by kabaddi team : 7, 17, 2, 5, 27, 15, 8, 14, 10, 48, 10, 7, 24, 8, 28, 18.

By formula,

Mean=Sum of pointsNo. of matches=7+17+2+5+27+15+8+14+10+48+10+7+24+8+28+1816=24816=15.5\text{Mean} = \dfrac{\text{Sum of points}}{\text{No. of matches}} \\[1em] = \dfrac{7 + 17 + 2 + 5 + 27+ 15 + 8 + 14 + 10 + 48 + 10 + 7 + 24 + 8 + 28 + 18}{16} \\[1em] = \dfrac{248}{16} \\[1em] = 15.5

Let’s arrange the given data in ascending order:

2, 5, 7, 7, 8, 8, 10, 10, 14, 15, 17, 18, 24, 27, 28, 48.

Here, n = 16 when is even

By formula,

Median=n2 th observation+(n2+1) th observation2=162 th observation+(162+1) th observation2=8 th observation+9 th observation2=10+142=242=12\text{Median} = \dfrac{\dfrac{n}{2}\text{ th observation} + \Big(\dfrac{n}{2} + 1\Big) \text{ th observation}}{2} \\[1em] = \dfrac{\dfrac{16}{2}\text{ th observation} + \Big(\dfrac{16}{2} + 1\Big)\text{ th observation}}{2} \\[1em] = \dfrac{8 \text{ th observation} + 9\text{ th observation}}{2} \\[1em] = \dfrac{10 + 14}{2} \\[1em] = \dfrac{24}{2} \\[1em] = 12

Hence, the mean and the median of the points scored by the Kabaddi team are 15.5 and 12 respectively.

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