The points A(9, 0), B(9, 6), C(-9, 6) and D(-9, 0) are the vertices of a

1. rectangle

2. square

3. rhombus

4. trapezium

We know that,

Distance-Formula = $\sqrt{(x$2 - x1)^2 + (y2 - y1)^2}

Given, A(9, 0), B(9, 6), C(-9, 6) and D(-9, 0)

Calculating the length of sides by distance formula.

$AB = \sqrt{(9 - 9)^2 + (6 - 0)^2} \\[1em] = \sqrt{0 + 36} \\[1em] = 6 \text{ units.} \\[1em] BC = \sqrt{(-9 - 9)^2 + (6 - 6)^2} \\[1em] = \sqrt{(-18)^2 + 0^2} \\[1em] = \sqrt{324} \\[1em] = 18 \text{ units.} \\[1em] CD = \sqrt{(-9 - (-9))^2 + (0 - 6)^2} \\[1em] = \sqrt{0 + 36} \\[1em] = \sqrt{36} \\[1em] = 6 \text{ units.} \\[1em] DA = \sqrt{(9 - (-9))^2 + (0 - 0)^2} \\[1em] = \sqrt{18^2 + 0} \\[1em] = \sqrt{324} \\[1em] = 18 \text{ units.}$

Since, AB = CD and BC = DA means opposite sides are equal.

Hence, Option 1 is the correct option.