The point P(-6, -3) is reflected in line y + 3 = 0 to point P'. The co-ordinates of point P' are :

1. (-6, 3)

2. (-6, -3)

3. (6, 3)

4. (6, -3)

Given,

Point P = (-6, -3) and Line : y + 3 = 0.

Substituting y-coordinate of point P on the line.

⇒ -3 + 3

⇒ 0.

Since, point P satisfies the equation of line.

∴ P lies on the line.

Since, a point is invariant under reflection on the line it lies.

∴ P' = (-6, -3).

Hence, Option 2 is the correct option.