The moment of a force of 25 N about a point is 2.5 N m. Find the perpendicular distance of force from that point.

Given:
Force f = 25 N
Moment of force = 2.5 N m
Perpendicular distance d = ?

$\text{Moment of force} = \text{force f} \times \text{distance d} \\[1em] \text{Distance d}= \dfrac{\text{Moment of force}}{\text{Force f}} \\[1em] = \dfrac{\text{2.5}}{\text{25}} \\[1em] = 0.1 \text{ m}$

So, perpendicular distance of force from the point = 0.1 m or 10 cm.