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The minimum angle of deviation is given by :

  1. δmin=2iAδ_ {min} = 2i - A
  2. δmin=2i+Aδ_ {min} = 2i + A
  3. δmin=2iAδ_ {min} = \dfrac{2i}{A}
  4. none of these

Refraction Plane Surfaces

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Answer

δmin=2iAδ_ {min} = 2i - A

Reason — In the position of minimum deviation, the refracted ray inside the prism is parallel to its base, if the prism is equilateral (or the principal section of prism forms an isosceles triangle). The minimum angle of deviation is given by δmin=2iAδ_ {min} = 2i - A

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