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Mathematics

The median of first six prime numbers is :

  1. 5

  2. 7

  3. 6

  4. 7.5

Statistics

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Answer

Prime numbers : 2, 3, 5, 7, 11, 13.

No. of terms (n) = 6, which is even.

Median = (n2) th term+(n2+1) th term2\dfrac{\Big(\dfrac{n}{2}\Big) \text{ th term} + \Big(\dfrac{n}{2} + 1\Big) \text{ th term}}{2}

Substituting values we get :

Median =(62) th term+(62+1) th term2=3rd term + 4th term2=5+72=122=6.\text{Median } = \dfrac{\Big(\dfrac{6}{2}\Big) \text{ th term} + \Big(\dfrac{6}{2} + 1\Big) \text{ th term}}{2} \\[1em] = \dfrac{\text{3rd term + 4th term}}{2} \\[1em] = \dfrac{5 + 7}{2} \\[1em] = \dfrac{12}{2} \\[1em] = 6.

Hence, Option 3 is the correct option.

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