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Mathematics

The mean of the following frequency distribution is 57.6 and the sum of all the frequencies is 50. Find the values of p and q :

ClassesFrequency
0 - 207
20 - 40p
40 - 6012
60 - 80q
80 - 1008
100 - 1205

Measures of Central Tendency

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Answer

We construct the following table :

Marks (Classes)Class mark (yi)Number of students (Frequency (fi))fiyi
0 - 2010770
20 - 4030p30p
40 - 605012600
60 - 8070q70q
80 - 100908720
100 - 1201105550
Total32 + p + q1940 + 30p + 70q

Given,

The sum of frequencies = 50.

∴ 32 + p + q = 50
⇒ p + q = 18
⇒ p = 18 - q      …..(i)

Mean=fiyifi57.6=1940+30p+70q5057.6×50=1940+30p+70q2880=1940+30p+70q30p+70q=2880194030p+70q=940\therefore \text{Mean} = \dfrac{∑fiyi}{∑f_i} \\[1em] \Rightarrow 57.6 = \dfrac{1940 + 30p + 70q}{50} \\[1em] \Rightarrow 57.6 \times 50 = 1940 + 30p + 70q \\[1em] \Rightarrow 2880 = 1940 + 30p + 70q \\[1em] \Rightarrow 30p + 70q = 2880 - 1940 \\[1em] \Rightarrow 30p + 70q = 940

Putting value of p from (i) in above equation,

30(18q)+70q=94054030q+70q=940540+40q=94040q=94054040q=400q=10\Rightarrow 30(18 - q) + 70q = 940 \\[1em] \Rightarrow 540 - 30q + 70q = 940 \\[1em] 540 + 40q = 940 \\[1em] 40q = 940 - 540 \\[1em] 40q = 400 \\[1em] q = 10

Using (i),

⇒ p = 18 - q = 18 - 10 = 8.

Hence, the value of p = 8 and q = 10.

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