The mean of data, represented by given diagram is : 1. 53 2. 47 3. 42 4. 51

Table from the given graph is : C.I. | Class mark (x) | Frequency (f) | fx -- | -- | --- | --- 40-50 | 45 | 40 | 1800 50-60 | 55 | 10 | 550 Total | | Σf = 50 | Σfx = 2350 By formula, Mean = = 47. Hence, Option 2 is the correct option.

The mean of observations, given in the adjoining table, is 20, the value of a is :
x f fx
10 10
20 a
30 10
20
30
10
25

x	f	fx
10	10
20	a
30	10

View Answer Bookmark Now

If the mean of the data given in adjoining table is 20, the relation between x₁ and x₂ is :
x f fx
10 x₁
20 20
30 x₂
x₁ + x₂ = 30
x₁ - x₂ = 15
x₁ - x₂ = 0
x₁ + x₂ = 20

x	f	fx
10	x₁
20	20
30	x₂

View Answer Bookmark Now

The following table gives the ages of 50 students of a class. Find the arithmetic mean of their ages.
Age (years) No. of students
16 - 18 2
18 - 20 7
20 - 22 21
22 - 24 17
24 - 26 3

Age (years)	No. of students
16 - 18	2
18 - 20	7
20 - 22	21
22 - 24	17
24 - 26	3

View Answer Bookmark Now

The following are the marks obtained by 70 boys in a class test.
Marks No. of boys
30 - 40 10
40 - 50 12
50 - 60 14
60 - 70 12
70 - 80 9
80 - 90 7
90 - 100 6
Calculate the mean by :
(i) Short-cut method
(ii) Step-deviation method

Marks	No. of boys
30 - 40	10
40 - 50	12
50 - 60	14
60 - 70	12
70 - 80	9
80 - 90	7
90 - 100	6

View Answer Bookmark Now

Mathematics

The mean of data, represented by given diagram is :
53
47
42
51

Statistics

Related Questions

The mean of observations, given in the adjoining table, is 20, the value of a is :
x f fx
10 10
20 a
30 10
20
30
10
25

If the mean of the data given in adjoining table is 20, the relation between x₁ and x₂ is :
x f fx
10 x₁
20 20
30 x₂
x₁ + x₂ = 30
x₁ - x₂ = 15
x₁ - x₂ = 0
x₁ + x₂ = 20

The following table gives the ages of 50 students of a class. Find the arithmetic mean of their ages.
Age (years) No. of students
16 - 18 2
18 - 20 7
20 - 22 21
22 - 24 17
24 - 26 3

The following are the marks obtained by 70 boys in a class test.
Marks No. of boys
30 - 40 10
40 - 50 12
50 - 60 14
60 - 70 12
70 - 80 9
80 - 90 7
90 - 100 6
Calculate the mean by :
(i) Short-cut method
(ii) Step-deviation method

Mathematics

The mean of data, represented by given diagram is :53474251

Statistics

Related Questions

The mean of observations, given in the adjoining table, is 20, the value of a is :xffx101020a301020301025

If the mean of the data given in adjoining table is 20, the relation between x1 and x2 is :xffx10x1202030x2x1 + x2 = 30x1 - x2 = 15x1 - x2 = 0x1 + x2 = 20

The following table gives the ages of 50 students of a class. Find the arithmetic mean of their ages.Age (years)No. of students16 - 18218 - 20720 - 222122 - 241724 - 263

The following are the marks obtained by 70 boys in a class test.MarksNo. of boys30 - 401040 - 501250 - 601460 - 701270 - 80980 - 90790 - 1006Calculate the mean by :(i) Short-cut method(ii) Step-deviation method

The mean of data, represented by given diagram is :
53
47
42
51

The mean of observations, given in the adjoining table, is 20, the value of a is :
x f fx
10 10
20 a
30 10
20
30
10
25

If the mean of the data given in adjoining table is 20, the relation between x₁ and x₂ is :
x f fx
10 x₁
20 20
30 x₂
x₁ + x₂ = 30
x₁ - x₂ = 15
x₁ - x₂ = 0
x₁ + x₂ = 20

The following table gives the ages of 50 students of a class. Find the arithmetic mean of their ages.
Age (years) No. of students
16 - 18 2
18 - 20 7
20 - 22 21
22 - 24 17
24 - 26 3

The following are the marks obtained by 70 boys in a class test.
Marks No. of boys
30 - 40 10
40 - 50 12
50 - 60 14
60 - 70 12
70 - 80 9
80 - 90 7
90 - 100 6
Calculate the mean by :
(i) Short-cut method
(ii) Step-deviation method