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Mathematics

The marks obtained (out of 50) by 40 students in a test are given below:

28, 31, 45, 03, 05, 18, 35, 46, 49, 17, 10, 28, 31, 36, 40, 44, 47, 13, 19, 25, 24, 31, 38, 32, 27, 19, 25, 28, 48, 15, 18, 31, 37, 46, 06, 01, 20, 10, 45, 02.

(i) Taking class intervals 1 – 10, 11 – 20, .., construct a tally chart and a frequency distribution table.

(ii) Convert the above distribution to continuous distribution.

(iii) State the true class limits of the third class.

(iv) State the class mark of the fourth class.

Statistics

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Answer

(i) The frequency distribution table for given grouped data is :

ClassesTally MarksFrequency
1 - 10IIII II7
11 - 20IIII III8
21 - 30IIII II7
31 - 40IIII IIII10
41 - 50IIII III8

(ii) Adjustment factor = (Lower limit of one class - Upper limit of previous class) / 2

=11102=12= \dfrac{11 - 10}{2} = \dfrac{1}{2} = 0.5

Subtracting the adjustment factor (0.5) from all the lower limits and add the adjustment factor (0.5) to all the upper limits.

Continuous frequency distribution for the given data is :

Classes before adjustmentClasses after adjustmentFrequency
1 - 100.5 - 10.57
11 - 2010.5 - 20.58
21 - 3020.5 - 30.57
31 - 4030.5 - 40.510
41 - 5040.5 - 50.58

(iii) Third class : 20.5 - 30.5

Hence, lower limit : 20.5 and upper limit : 30.5

(iv) Class mark = Lower limit + Upper limit2\dfrac{\text{Lower limit + Upper limit}}{2}

= 30.5+40.52=712\dfrac{30.5 + 40.5}{2} = \dfrac{71}{2} = 35.5

Hence, class mark of fourth class = 35.5

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