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Mathematics

The marks obtained by 120 students in a Mathematics test are given below:

MarksNo. of students
0 - 105
10 - 209
20 - 3016
30 - 4022
40 - 5026
50 - 6018
60 - 7011
70 - 806
80 - 904
90 - 1003

Draw an ogive for the given distribution on a graph sheet. Use a suitable scale for ogive to estimate the following :

(i) the median

(ii) the number of students who obtained more than 75% marks in the test.

(iii) the number of students who did not pass in the test if the pass percentage was 40.

Measures of Central Tendency

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Answer

  1. The cumulative frequency table for the given continuous distribution is :
MarksNo. of studentsCumulative frequency
0 - 1055
10 - 20914
20 - 301630
30 - 402252
40 - 502678
50 - 601896
60 - 7011107
70 - 806113
80 - 904117
90 - 1003120
  1. Take 1 cm along x-axis = 10 marks

  2. Take 1 cm along y-axis = 10 students

  3. Plot the points (10, 5), (20, 14), (30, 30), (40, 52), (50, 78), (60, 96), (70, 107), (80, 113), (90, 117) and (100, 120) representing upper class limits and the respective cumulative frequencies.
    Also plot the point representing lower limit of the first class i.e. 0 - 10.

  4. Join these points by a freehand drawing.

The marks obtained by 120 students in a Mathematics test are given below. Draw an ogive for the given distribution on a graph sheet. Use a suitable scale for ogive to estimate the median, the number of students who obtained more than 75% marks in the test, the number of students who did not pass in the test if the pass percentage was 40. Measures of Central Tendency, ML Aggarwal Understanding Mathematics Solutions ICSE Class 10.

The required ogive is shown in figure above.

(i) Here, n (no. of students) = 120.

To find the median :

Let A be the point on y-axis representing frequency = n2=1202\dfrac{n}{2} = \dfrac{120}{2} = 60.

Through A draw a horizontal line to meet the ogive at P. Through P, draw a vertical line to meet the x-axis at M. The abscissa of the point M represents marks = 43.5

Hence, the median marks = 43.5.

(ii) Total marks = 100.

75% marks = 75 numbers.

Let O be the point on x-axis representing marks = 75.

Through O draw a vertical line to meet the ogive at R. Through R, draw a horizontal line to meet the y-axis at C. The ordinate of the point C represents 110.

Hence, 110 students score less than 75 so students scoring more than 75 = 120 - 110 = 10.

Hence, 10 students score more than 75% in the test.

(iii) 40% of 100 = 40.

Let T be the point on x-axis representing marks = 40.

Through T, draw a vertical line to meet the ogive at S. Through S, draw a horizontal line to meet the y-axis at D. The ordinate of the point D represents 52.

No. of students who scored less than 40 marks = 52.

Hence, 52 students failed in the examination.

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