The magnification by a lens is +0.5. Name the lens and state how are u and v related?

As the magnification (m) of the lens is given as +0.5, which implies that the image is virtual and erect because m is positive for a virtual and erect image. The image is smaller in size as the magnitude of magnification is smaller than 1. As the image formed is virtual, erect and smaller in size so the lens used is concave in nature. As we know, the relation between u and v is as shown below Given, magnification by a lens is +0.5 Substituting the values in the formula The lens is concave in nature and the image distance v = 0.5u.

The power of a lens is -2.0 D. Find its focal length and its kind.

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The magnification by a lens is -3. Name the lens and state how are u and v related?

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A concave lens has a focal length of 30 cm. Find the position and magnification (m) of the image for an object placed in front of it at a distance of 30 cm. State whether the image is real or virtual ?

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Find the position and magnification of the image of an object placed at distance of 8.0 cm in front of a convex lens of focal length 10.0 cm. Is the image erect or inverted?

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Physics

The magnification by a lens is +0.5. Name the lens and state how are u and v related?

Refraction Lens

Related Questions

The power of a lens is -2.0 D. Find its focal length and its kind.

The magnification by a lens is -3. Name the lens and state how are u and v related?

A concave lens has a focal length of 30 cm. Find the position and magnification (m) of the image for an object placed in front of it at a distance of 30 cm. State whether the image is real or virtual ?

Find the position and magnification of the image of an object placed at distance of 8.0 cm in front of a convex lens of focal length 10.0 cm. Is the image erect or inverted?