The line 2x - 3y = 12, meets x-axis at point A and y-axis at point B, then : 1. A = (6, 0) and B = (0, -4) 2. A = (0, -4) and B = (6, 0) 3. A = (0, -4) and B = (-6, 0) 4. A = (-6, 0) and B = (4, 0)

We know that, y-coordinate at x-axis = 0. Let point A be (a, 0). Since, Line 2x - 3y = 12 meets x-axis at point A. ∴ Point A(a, 0) satisfies the equation 2x - 3y = 12. ⇒ 2a - 3(0) = 12 ⇒ 2a - 0 = 12 ⇒ 2a = 12 ⇒ a = = 6. ∴ A = (a, 0) = (6, 0). We know that, x-coordinate at y-axis = 0. Let point B be (0, b). Since, Line 2x - 3y = 12 meets y-axis at point B. ∴ Point B(0, b) satisfies the equation 2x - 3y = 12. ⇒ 2(0) - 3b = 12 ⇒ 0 - 3b = 12 ⇒ -3b = 12 ⇒ b = = -4. ∴ B = (0, b) = (0, -4). Hence, Option 1 is the correct option.

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Mathematics

The line 2x - 3y = 12, meets x-axis at point A and y-axis at point B, then :
A = (6, 0) and B = (0, -4)
A = (0, -4) and B = (6, 0)
A = (0, -4) and B = (-6, 0)
A = (-6, 0) and B = (4, 0)

Straight Line Eq

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Mathematics

The line 2x - 3y = 12, meets x-axis at point A and y-axis at point B, then :
A = (6, 0) and B = (0, -4)
A = (0, -4) and B = (6, 0)
A = (0, -4) and B = (-6, 0)
A = (-6, 0) and B = (4, 0)

Straight Line Eq

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Mathematics

The line 2x - 3y = 12, meets x-axis at point A and y-axis at point B, then :A = (6, 0) and B = (0, -4)A = (0, -4) and B = (6, 0)A = (0, -4) and B = (-6, 0)A = (-6, 0) and B = (4, 0)

Straight Line Eq

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The line 2x - 3y = 12, meets x-axis at point A and y-axis at point B, then :
A = (6, 0) and B = (0, -4)
A = (0, -4) and B = (6, 0)
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Point P divides the line segment joining the points A (8, 0) and B (16, -8) in the ratio 3 : 5. Find its co-ordinates of point P.
Also, find the equation of the line through P and parallel to 3x + 5y = 7.

The equation of line AB is x + 8 = 0. The slope of the line OP which bisects angle O, is :
1
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The vertices A and C of rhombus ABCD are A = (3, -1) and C = (-4, -8). The slope of diagonal BD is :
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