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Physics

The force of attraction between two masses each of 1 kg kept at a separation of 1 m is —

  1. 9.8 N
  2. 6.7 N
  3. 980 N
  4. 6.7 x 10-11 N

Laws of Motion

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Answer

6.7 x 10-11 N

Reason — As we know,

F = G m1m2r2\dfrac{m1 m2}{r^2} and

Given,

r = 1 m

weight of masses = 1 kg each

G = 6.7 x 10 -11 N m 2 kg-2

Substituting the values in the formula above, we get,

F=(6.7×1011)×1×112F=6.7×1011F = \dfrac {(6.7 \times 10^{-11}) \times 1 \times 1}{1^2} \\[0.5em] \Rightarrow F = 6.7 \times 10^{-11} \\[0.5em]

Hence,

the force of attraction = 6.7 x 10-11 N

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