Mathematics
The following table gives the life time in days of 100 electricity tubes of a certain make :
Lifetime in days | No. of tubes |
---|---|
less than 50 | 8 |
less than 100 | 23 |
less than 150 | 55 |
less than 200 | 81 |
less than 250 | 93 |
less than 300 | 100 |
Find the mean lifetime of electricity tubes.
Measures of Central Tendency
55 Likes
Answer
We construct the following table :
Lifetime in days (Classes) | Class mark (yi) | No. of tubes (Cumulative frequency) | Frequency (fi)) | fiyi |
---|---|---|---|---|
0 - 50 | 25 | 8 | 8 | 200 |
50 - 100 | 75 | 23 | 23 - 8 = 15 | 1125 |
100 - 150 | 125 | 55 | 55 - 23 = 32 | 4000 |
150 - 200 | 175 | 81 | 81 - 55 = 26 | 4550 |
200 - 250 | 225 | 93 | 93 - 81 = 12 | 2700 |
250 - 300 | 275 | 100 | 100 - 93 = 7 | 1925 |
Total | 100 | 14500 |
∴ Mean = = 145
Hence, mean of the following distribution is 145 days
Answered By
33 Likes
Related Questions
If the mean of the following distribution is 24, find the value of a :
Marks Number of students 0 - 10 7 10 - 20 a 20 - 30 8 30 - 40 10 40 - 50 5 The mean of the following frequency distribution is 57.6 and the sum of all the frequencies is 50. Find the values of p and q :
Classes Frequency 0 - 20 7 20 - 40 p 40 - 60 12 60 - 80 q 80 - 100 8 100 - 120 5 Using the information given in the adjoining histogram, calculate the mean correct to one decimal place.
A student scored the following marks in 11 questions of a question paper :
3, 4, 7, 2, 5, 6, 1, 8, 2, 5, 7.
Find the median marks.