Mathematics
The following table gives the daily wages of workers in a factory :
| Wages in ₹ | No. of workers |
|---|---|
| 45 - 50 | 5 |
| 50 - 55 | 8 |
| 55 - 60 | 30 |
| 60 - 65 | 25 |
| 65 - 70 | 14 |
| 70 - 75 | 12 |
| 75 - 80 | 6 |
Calculate their mean by short cut method.
Measures of Central Tendency
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Answer
We construct the following table, taking assumed mean as 62.5
| Wages in ₹ (Classes) | Class mark (yi) | Deviation (di = yi - a) | No. of workers (Frequency (fi)) | fidi |
|---|---|---|---|---|
| 45 - 50 | 47.5 | -15 | 5 | -75 |
| 50 - 55 | 52.5 | -10 | 8 | -80 |
| 55 - 60 | 57.5 | -5 | 30 | -150 |
| 60 - 65 | 62.5 | 0 | 25 | 0 |
| 65 - 70 | 67.5 | 5 | 14 | 70 |
| 70 - 75 | 72.5 | 10 | 12 | 120 |
| 75 - 80 | 77.5 | 15 | 6 | 90 |
| Total | 100 | -25 |
Hence, mean of the following distribution is ₹62.25
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