The equation of a line AB is 2x - 2y + 3 = 0.

(i) Find the slope of the line AB.

(ii) Calculate the angle that the line AB makes with the positive direction of the x-axis.

(i) Given,

⇒ 2x - 2y + 3 = 0

⇒ 2y = 2x + 3

⇒ y = $x + \dfrac{3}{2}$.

Comparing above equation with y = mx + c we get,

Slope = 1.

Hence, slope of line AB = 1.

(ii) Let angle be θ.

By formula,

⇒ Slope = tan θ

⇒ tan θ = 1

⇒ tan θ = tan 45°

⇒ θ = 45°.

Hence, angle that line makes with positive direction of x-axis = 45°.