Mathematics
The data on the number of patients attending a hospital in a month is given below. Find the average (mean) number of patients attending the hospital in a month using the short cut method.
Take assumed mean as 45. Give your answer correct to 2 decimal places.
| Number of patients | Number of days |
|---|---|
| 10 - 20 | 5 |
| 20 - 30 | 2 |
| 30 - 40 | 7 |
| 40 - 50 | 9 |
| 50 - 60 | 2 |
| 60 - 70 | 5 |
Measures of Central Tendency
15 Likes
Answer
Construct table as under, taking assumed mean a = 45.
| Number of patients (Classes) | Class mark (yi) | Deviation (di = yi - a) | Number of days (Frequency (fi)) | fidi |
|---|---|---|---|---|
| 10 - 20 | 15 | -30 | 5 | -150 |
| 20 - 30 | 25 | -20 | 2 | -40 |
| 30 - 40 | 35 | -10 | 7 | -70 |
| 40 - 50 | 45 | 0 | 9 | 0 |
| 50 - 60 | 55 | 10 | 2 | 20 |
| 60 - 70 | 65 | 20 | 5 | 100 |
| Total | 30 | -140 |
Hence, mean of the following distribution is 40.33
Answered By
8 Likes
Related Questions
Calculate the mean of the following distribution :
Class interval Frequency 0 - 10 8 10 - 20 5 20 - 30 12 30 - 40 35 40 - 50 24 50 - 60 16 Calculate the mean of the following distribution using step deviation method :
Marks Number of students 0 - 10 10 10 - 20 9 20 - 30 25 30 - 40 30 40 - 50 16 50 - 60 10 The following table gives the daily wages of workers in a factory :
Wages in ₹ No. of workers 45 - 50 5 50 - 55 8 55 - 60 30 60 - 65 25 65 - 70 14 70 - 75 12 75 - 80 6 Calculate their mean by short cut method.
Calculate the mean of the distribution given below using the short cut method.
Marks No. of students 11 - 20 2 21 - 30 6 31 - 40 10 41 - 50 12 51 - 60 9 61 - 70 7 71 - 80 4