KnowledgeBoat Logo
|

Mathematics

The daily output of 19 workers is :

41, 21, 38, 27, 31, 45, 23, 26, 29, 30, 28, 25, 35, 42, 47, 53, 29, 31, 35.

Find :

(i) the median

(ii) lower quartile

(iii) upper quartile

(iv) inter quartile range

Measures of Central Tendency

70 Likes

Answer

On arranging the given wages in ascending order we get,

21, 23, 25, 26, 27, 28, 29, 29, 30, 31, 31, 35, 35, 38, 41, 42, 45, 47, 53.

Here, n (no. of observations) = 19, which is odd.

(i) As n is odd,

Median=n+12th observation=19+12=202=10th observation\therefore \text{Median} = \dfrac{n + 1}{2} \text{th observation} \\[1em] = \dfrac{19 + 1}{2} \\[1em] = \dfrac{20}{2} \\[1em] = 10 \text{th observation}

∴ Median = 10th observation = 31.

Hence, median = 31.

(ii) As n is odd,

Lower quartile(Q1)=n+14th observation=19+14=204=5th observation\therefore \text{Lower quartile} (Q_1) = \dfrac{n + 1}{4} \text{th observation} \\[1em] = \dfrac{19 + 1}{4} \\[1em] = \dfrac{20}{4} \\[1em] = 5 \text{th observation}

∴ Lower quartile (Q1) = 5th observation = 27.

Hence, lower quartile = 27.

(iii) As n is odd,

Upper quartile(Q3)=3(n+1)4th observation=3(19+1)4=604=15th observation\therefore \text{Upper quartile} (Q_3) = \dfrac{3(n + 1)}{4} \text{th observation} \\[1em] = \dfrac{3(19 + 1)}{4} \\[1em] = \dfrac{60}{4} \\[1em] = 15 \text{th observation}

∴ Upper quartile (Q3) = 15th observation = 41.

Hence, upper quartile = 41.

(iv) Inter quartile range = Q3 - Q1 = 41 - 27 = 14.

Hence, inter quartile range = 14.

Answered By

28 Likes


Related Questions