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Mathematics

The daily expenditure of 100 families are given below. Calculate f1 and f2, if the mean daily expenditure is ₹188.

Expenditure (in ₹)No. of families
140 - 1605
160 - 18025
180 - 200f1
200 - 220f2
220 - 2405

Measures of Central Tendency

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Answer

We construct the table as under :

Expenditure (in ₹)Class mark (ui)No. of families (fi)fiui
140 - 1601505750
160 - 180170254250
180 - 200190f1190f1
200 - 220210f2210f2
220 - 24023051150
Total35 + f1 + f26150 + 190f1 + 210f2

As there are 100 families,

∴ 35 + f1 + f2 = 100
⇒ f1 + f2 = 100 - 35 = 65
⇒ f1 = 65 - f2      ……(i)

Mean=ΣfiuiΣfi188=6150+190f1+210f235+f1+f2188(35+f1+f2)=6150+190f1+210f2188(35+65f2+f2)=6150+190(65f2)+210f2 …….(Using (i))188(100)=6150+12350190f2+210f218800=18500+20f21880018500=20f220f2=300f2=15.\text{Mean} = \dfrac{Σfiui}{Σfi} \\[1em] \Rightarrow 188 = \dfrac{6150 + 190f1 + 210f2}{35 + f1 + f2} \\[1em] \Rightarrow 188(35 + f1 + f2) = 6150 + 190f1 + 210f2 \\[1em] \Rightarrow 188(35 + 65 - f2 + f2) = 6150 + 190(65 - f2) + 210f2 \text{ …….(Using (i))} \\[1em] \Rightarrow 188(100) = 6150 + 12350 - 190f2 + 210f2 \\[1em] \Rightarrow 18800 = 18500 + 20f2 \\[1em] \Rightarrow 18800 - 18500 = 20f2 \\[1em] \Rightarrow 20f2 = 300 \\[1em] \Rightarrow f_2 = 15.

Using (i),

⇒ f1 = 65 - f2 = 65 - 15 = 50.

Hence, f1 = 50 and f2 = 15.

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