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Mathematics

The circumference of the base of a cylindrical vessel is 132 cm and its height is 25 cm. Find the

(i) radius of the cylinder.

(ii) volume of the cylinder.

Mensuration

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Answer

(i) Circumference = 2πr.

Given, circumference = 132 cm.

∴ 2πr = 132

2×227r2 \times \dfrac{22}{7}r = 132

⇒ r = 132×72×22=92444\dfrac{132 \times 7}{2 \times 22} = \dfrac{924}{44} = 21 cm.

Hence, the radius of the cylinder = 21 cm.

(ii) Given height = 25 cm.

Volume of cylinder = πr2h.

Putting values we get,

Volume of cylinder =227×(21)2×25=22×441×257=2425507=34650 cm3.\text{Volume of cylinder } = \dfrac{22}{7} \times (21)^2 \times 25 \\[1em] = \dfrac{22 \times 441 \times 25}{7} \\[1em] = \dfrac{242550}{7} \\[1em] = 34650 \text{ cm}^3.

Hence, the volume of the cylinder = 34650 cm3.

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