The base of a container measures 15 cm x 20 cm. It is placed on a table top. If the weight of the container is 60 N, what is the pressure exerted by the container on the table top?

Given:
Weight = Thrust = 60 N
Area = 15 cm x 20 cm = 300 cm² = $\dfrac{\text{300}}{\text{10000}}$ = 0.03 m²
Pressure = ?

$\text{Pressure}= \dfrac{\text{Thrust}}{\text{Area}} \\[1em] = \dfrac{\text{60}}{\text{0.03}} \\[1em] = 2000 \text{ Pa}$

So, Pressure = 2000 Pa.