Mathematics
The age of a man is twice the square of the age of his son. Eight years hence, the age of the man will be 4 years more than 3 times the age of his son. Find their present ages.
Related Questions
Paul is x years old and his father's age is twice the square of Paul's age. Ten years hence, father's age will be four times Paul's age. Find their present ages.
Two years ago, a man's age was three times the square of his daughter's age . Three years hence , his age will be four times his daughter's age . Find their present ages.
The sum of the ages of Vivek and his youger brother Amit is 47 years. The product of their ages in years is 550. Find their ages.
The length (in cm) of the hypotenuse of a right angled triangle exceeds the length of one side by 2 cm and exceeds twice the length of other side by 1 cm. Find the length of each side. Also find the perimeter and the area of the triangle.