Mathematics

The 17th term of an AP exceeds its 10th term by 7. Find the common difference.

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Let first term of A.P. be a and common difference be d.

By formula,

a_n = a + (n - 1)d

Given,

17th term of an AP exceeds its 10th term by 7.

∴ a₁₇ - a₁₀ = 7

⇒ a + (17 - 1)d - [a + (10 - 1)d] = 7

⇒ a + 16d - [a + 9d] = 7

⇒ a - a + 16d - 9d = 7

⇒ 7d = 7

⇒ d = $\dfrac{7}{7}$ = 1.

Hence, common difference = 1.

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