Table SALES

Column Name
STORE_ID
SALES_DATE
SALES_AMOUNT

Which SQL statement allows you to find the total sales amount for Store ID 25 and the total sales amount for Store ID 45?

1. SELECT STORE_ID, SUM(SALES_AMOUNT) FROM SALES
   WHERE STORE_ID IN (25, 45) GROUP BY STORE_ID;
2. SELECT STORE_ID, SUM(SALES_AMOUNT) FROM SALES
   GROUP BY STORE_ID HAVING STORE_ID IN (25, 45);
3. SELECT STORE_ID, SUM(SALES_AMOUNT) FROM SALES WHERE STORE_ID IN (25, 45);
4. SELECT STORE_ID, SUM(SALES_AMOUNT) FROM SALES
   WHERE STORE_ID = 25 AND STORE_ID = 45 GROUP BY STORE_ID;

SELECT STORE_ID, SUM(SALES_AMOUNT) FROM SALES   
WHERE STORE_ID IN (25, 45) GROUP BY STORE_ID;

Explanation

1. SELECT STORE_ID, SUM(SALES_AMOUNT) FROM SALES WHERE STORE_ID IN (25, 45) GROUP BY STORE_ID; — This query uses the IN operator to filter rows where the STORE_ID is either 25 or 45. It then calculates the total sales amount for each store ID using SUM(SALES_AMOUNT) and groups the results by STORE_ID. This query correctly finds the total sales amount for Store ID 25 and Store ID 45 separately.
2. SELECT STORE_ID, SUM(SALES_AMOUNT) FROM SALES GROUP BY STORE_ID HAVING STORE_ID IN (25, 45); — This query will also give the required output but it is inefficient because it first retrieves all rows from the "SALES" table, then groups the results by store ID, and finally filters the result set to include only store IDs 25 and 45. The inefficiency arises from the fact that it processes all rows in the "SALES" table before filtering out the unnecessary data. This means that it processes more data than necessary, which can be wasteful in terms of computational resources and time. A more efficient approach would be to select only the rows having store IDs 25 and 45 first (using WHERE clause), and then perform the aggregation.
3. SELECT STORE_ID, SUM(SALES_AMOUNT) FROM SALES WHERE STORE_ID IN (25, 45); — This query filters rows where the STORE_ID is either 25 or 45 and calculates the total sales amount for these store IDs using SUM(SALES_AMOUNT). However, it doesn't include a GROUP BY clause, so it would return a single row with the total sales amount for both Store ID 25 and Store ID 45 combined.
4. SELECT STORE_ID, SUM(SALES_AMOUNT) FROM SALES WHERE STORE_ID = 25 AND STORE_ID = 45 GROUP BY STORE_ID; — This query filter rows where the STORE_ID is both 25 and 45 simultaneously using STORE_ID = 25 AND STORE_ID = 45. However, this condition is impossible to satisfy because a single value cannot be both 25 and 45 at the same time. Therefore, this query would not return any results.