Study the velocity-time graph shown below and answer the questions that follow:

(i) The distance travelled in 5s:

1. 10 m
2. 50 m
3. 125 m
4. 250 m

(ii) The retardation of the body as calculated from the graph is:

1. 12 ms^-2
2. 15 ms^-2
3. 10 ms^-2
4. 20 ms^-2

(i) 125 m
Reason — Area under the velocity-time graph will give the distance travelled in 5 secs:

Area = $\dfrac{1}{2}$ x base x height

= $\dfrac{1}{2}$ x 5 x 50

= $\dfrac{250}{2}$

= 125 m

Hence, distance travelled in 5s = 125 m

(ii) 10 ms^-2
Reason —

$\text{Retardation} = \text{Slope of straight line} \\[1em] = \dfrac{(50 - 0)}{(5 - 0)} \\[1em] = \dfrac{50 \text{ m}}{5 \text{ s}} \\[1em] = 10 \text{ m s}^{-2}$

Hence, retardation = 10 ms^-2