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Chemistry

State which of the following are better fertilizers —

(i) Potassium phosphate [K3PO4] or potassium nitrate [KNO3]

(ii) Urea [NH2CONH2] or ammonium phosphate [(NH4)3PO4]

[K = 39, P = 31, O = 16, N = 14, H = 1]

Stoichiometry

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Answer

(i) Molecular weight of K3PO4 = 3(39) + 31 + 4(16) = 117 + 31 + 64 = 212 g

Percentage of K in K3PO4 = 117212\dfrac{117}{212} x 100 = 55.18%

Molecular weight of [KNO3] = 39 + 14 + 3(16) = 39 + 14 + 48 = 101 g

Percentage of K in KNO3 = 39101\dfrac{39}{101} x 100 = 38.61%

Hence, potassium phosphate (% of K = 55.18 %) is better fertilizer than potassium nitrate (% of K = 38.61 %).

(ii) Molecular weight of NH2CONH2 = 14 + 2(1) + 12 + 16 + 14 + 2(1) = 14 + 2 + 12 + 16 + 14 + 2 = 60 g

Percentage of N in NH2CONH2 = 2860\dfrac{28}{60} x 100 = 46.67%

Molecular weight of (NH4)3PO4 = 3[14 + 4(1)] + 31 + 4(16) = 54 + 31 + 64 = 149 g

Percentage of N in (NH4)3PO4 = 42149\dfrac{42}{149} x 100 = 28.19%

Hence, Urea is a better fertilizer as percentage of N in urea is 46.67% and in (NH4)3PO4 is 28.19 %

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