State the numerical value of the frequency of oscillation of a seconds’ pendulum. Does it depend on the amplitude of oscillation ?

As we know that,

$f = \dfrac{1}{T}$

and T for a seconds’ pendulum = 2s.

So, substituting the value of T in equation above we get,

$f = \dfrac{1}{2} \\[0.5em] \Rightarrow f = 0.5$

Hence, the numerical value of the frequency of oscillation of a seconds’ pendulum is 0.5 s^-1.

No, it does not depend on the amplitude of oscillation.