Computer Science

State the final value of q at the end of the following program segment after execution. Show the dry run.

for(m=2;m<=3;++m)
{
for(n=1;n<=m;++n)
{
p=m+n-1;
if(p%3 == 0)
q += p;
else
q += p+4;
}
}

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Final value of q = 29.

Dry Run

m	n	p	q	Remarks
0	0	0	0	Assuming initial value of all variables to be zero.
2	0	0	0	First iteration of outer loop begins, m is initialized to 2.
2	1	0	0	First iteration of inner loop begins, n is initialized to 1.
2	1	2	0	p = 2 + 1 - 1 = 2
2	1	2	6	q = 0 + 2 + 4 = 6 as p%3 != 0
2	2	2	6	Second iteration of inner loop begins, n is incremented to 2.
2	2	3	6	p = 2 + 2 - 1 = 3
2	2	3	9	q = 6 + 3 = 9 as p%3 == 0
2	3	3	9	Inner loop terminates as n becomes greater than m.
3	3	3	9	Second iteration of outer loop begins, m is incremented to 3.
3	1	3	9	Inner loop restarts from first iteration, n is initialized to 1..
3	1	3	9	p = 3 + 1 - 1 = 3
3	1	3	12	q = 9 + 3 = 12 as p%3 == 0
3	2	3	12	Second iteration of inner loop begins, n is incremented to 2.
3	2	4	12	p = 3 + 2 - 1 = 4
3	2	4	20	q = 12 + 4 + 4 = 20 as p%3 != 0
3	3	4	20	Third iteration of inner loop begins, n is incremented to 3.
3	3	5	20	p = 3 + 3 - 1 = 5
3	3	5	29	q = 20 + 5 + 4 = 29 as p%3 != 0
4	3	5	29	Outer loop terminates as m becomes greater than 3, final value of q is 29.

Answered By

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if (a==1)
{
b += 10;
System.out.println(b);
}
else if (a == 2)
{
b -= 10;
System.out.println(b);
}
else
{
b *= a;
System.out.println(b); 
}