Chemistry
State – How will you distinguish between dilute hydrochloric acid and dilute sulphuric acid using lead nitrate solution.
Answer
Sulphuric acid forms a white precipitate with lead nitrate solution. This precipitate does not dissolve on warming the reaction mixture.
H2SO4 (dil.) + Pb(NO3)2 ⟶ 2HNO3 + PbSO4 ↓ [white ppt. formed which does not dissolve on warming the mixture].
Hydrochloric acid forms a white precipitate with lead nitrate solution. This precipitate dissolves on warming the reaction mixture so as to form clear solution.
2HCl (dil.) + Pb(NO3)2 ⟶ 2HNO3 + PbCl2 ↓ [white ppt. formed which dissolves on warming the mixture].
Hence, dilute hydrochloric acid and dilute sulphuric acid can be distinguished using lead nitrate solution.
Related Questions
Write the balanced chemical equation for – Action of concentrated sulphuric acid on sulphur.
State one relevant observation for – Action of conc. sulphuric acid on hydrated copper sulphate.
Write balanced chemical equations to show –
(i) The oxidizing action of conc. sulphuric acid on carbon.
(ii) The behaviour of H2SO4 as an acid when it reacts with magnesium.
(iii) The dehydrating property of conc. sulphuric acid with sugar.
(iv) The conversion of SO3 to sulphuric acid in the Contact process.
Choose the correct answer from the options given:
The catalyst used in the Contact Process is:
- Copper
- Iron
- Vanadium pentoxide
- Manganese dioxide