Solve the following equation:

(3x + 1)(2x + 3) = 3

Given, (3x + 1)(2x + 3) = 3

⇒ 6x² + 9x + 2x + 3 = 3

⇒ 6x² + 11x + 3 - 3 = 0

⇒ 6x² + 11x = 0

⇒ x(6x + 11) = 0

⇒ x = 0 or 6x + 11 = 0

⇒ x = 0 or 6x = -11

⇒ x = 0 or x = -$\dfrac{11}{6}$.

Hence, roots of the given equations are 0, $-\dfrac{11}{6}$