Solution of equations x - 2y = 7 and 2x - y = 8 is : 1. x = 3, y = 2 2. x = -3, y = 2 3. x = 3, y = -2 4. x = -3, y = -2

Given, Equations : x - 2y = 7 and 2x - y = 8. ⇒ x - 2y = 7 ⇒ x = 7 + 2y ........(1) Substituting value of x from equation (1) in 2x - y = 8, we get : ⇒ 2(7 + 2y) - y = 8 ⇒ 14 + 4y - y = 8 ⇒ 3y = 8 - 14 ⇒ 3y = -6 ⇒ y = = -2. Substituting value of y in equation (1), we get : ⇒ x = 7 + 2 × -2 = 7 - 4 = 3. Hence, Option 3 is the correct option.

Mathematics

Solution of equations x - 2y = 7 and 2x - y = 8 is :
x = 3, y = 2
x = -3, y = 2
x = 3, y = -2
x = -3, y = -2

Linear Equations

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Answer

Given,

Equations : x - 2y = 7 and 2x - y = 8.

⇒ x - 2y = 7

⇒ x = 7 + 2y ……..(1)

Substituting value of x from equation (1) in 2x - y = 8, we get :

⇒ 2(7 + 2y) - y = 8

⇒ 14 + 4y - y = 8

⇒ 3y = 8 - 14

⇒ 3y = -6

⇒ y = $-\dfrac{6}{3}$ = -2.

Substituting value of y in equation (1), we get :

⇒ x = 7 + 2 × -2 = 7 - 4 = 3.

Hence, Option 3 is the correct option.

Answered By

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Mathematics

Solution of equations x - 2y = 7 and 2x - y = 8 is :
x = 3, y = 2
x = -3, y = 2
x = 3, y = -2
x = -3, y = -2

Linear Equations

Answer

Related Questions

Solution of equations x + y = 2.1 and x - y = 0.3 is :
x = 1.2, y = 0.9
x = 1.2, y = -0.9
x = -1.2, y = 0.9
x = -1.2, y = -0.9

Solution of equations $\dfrac{1}{x} + \dfrac{1}{y} = 21 \text{ and } \dfrac{1}{x} - \dfrac{1}{y} + 9 = 0$ is :
$x = \dfrac{1}{6}, y = -\dfrac{1}{15}$
$x = -\dfrac{1}{6}, y = \dfrac{1}{15}$
$x = -\dfrac{1}{6}, y = -\dfrac{1}{15}$
$x = \dfrac{1}{6}, y = \dfrac{1}{15}$

Solution of equations $\dfrac{x}{2} - \dfrac{y}{3} = 0 \text{ and } \dfrac{x}{2} + \dfrac{y}{3} = 6$ is :
x = 6, y = -9
x = 6, y = 9
x = -6, y = -9
x = -6, y = 9

Solution of equations $\dfrac{x + 8}{5} - \dfrac{2y - 4}{3} = 0$ and y - x = 3 is :
x = 2, y = 5
x = -2, y = 5
x = 2, y = -5
x = -2, y = -5

Mathematics

Solution of equations x - 2y = 7 and 2x - y = 8 is :x = 3, y = 2x = -3, y = 2x = 3, y = -2x = -3, y = -2

Linear Equations

Answer

Related Questions

Solution of equations x + y = 2.1 and x - y = 0.3 is :x = 1.2, y = 0.9x = 1.2, y = -0.9x = -1.2, y = 0.9x = -1.2, y = -0.9

Solution of equations x2−y3=0 and x2+y3=6\dfrac{x}{2} - \dfrac{y}{3} = 0 \text{ and } \dfrac{x}{2} + \dfrac{y}{3} = 62x​−3y​=0 and 2x​+3y​=6 is :x = 6, y = -9x = 6, y = 9x = -6, y = -9x = -6, y = 9

Solution of equations x+85−2y−43=0\dfrac{x + 8}{5} - \dfrac{2y - 4}{3} = 05x+8​−32y−4​=0 and y - x = 3 is :x = 2, y = 5x = -2, y = 5x = 2, y = -5x = -2, y = -5

Solution of equations x - 2y = 7 and 2x - y = 8 is :
x = 3, y = 2
x = -3, y = 2
x = 3, y = -2
x = -3, y = -2

Solution of equations x + y = 2.1 and x - y = 0.3 is :
x = 1.2, y = 0.9
x = 1.2, y = -0.9
x = -1.2, y = 0.9
x = -1.2, y = -0.9

Solution of equations $\dfrac{x}{2} - \dfrac{y}{3} = 0 \text{ and } \dfrac{x}{2} + \dfrac{y}{3} = 6$ is :
x = 6, y = -9
x = 6, y = 9
x = -6, y = -9
x = -6, y = 9

Solution of equations $\dfrac{x + 8}{5} - \dfrac{2y - 4}{3} = 0$ and y - x = 3 is :
x = 2, y = 5
x = -2, y = 5
x = 2, y = -5
x = -2, y = -5