Chemistry
Solution A is a strong acid
Solution B is a weak acid
Solution C is a strong alkali
(i) Which solution contains solute molecules in addition to water molecules?
(ii) Which solution will give a gelatinous white precipitate with zinc sulphate solution? The precipitate disappears when an excess of the solution is added.
(iii) Which solution could be glacial acetic acid solution?
(iv) Give example of a soln. of a weak alkali.
Answer
(i) Solution B — weak acid
Reason — Weak Acid is an acid which dissociates only partially in aqueous solution thereby producing a low concentration of hydrogen [H+] ions [or H3O+ ions]. For example — CH3COOH ⇌ CH3COO- + H+ [contains molecules and ions]
(ii) Solution C — strong alkali
Reason — Alkalis react with certain salt solutions to precipitate insoluble hydroxide. Hence,
ZnSO4 + 2NaOH ⟶ Na2SO4 + Zn(OH)2 [gelatinous white precipitate]
(iii) Solution B — weak acid
Reason — Anhydrous acetic acid on cooling forms crystals of glacial acetic acid and acetic acid is a weak acid.
(iv) Ammonium hydroxide (NH4OH)
Related Questions
The acid which contains four hydrogen atoms is :
- Formic acid
- Sulphuric acid
- Nitric acid
- Acetic acid
A black coloured solid which on reaction with dilute sulphuric acid forms a blue coloured solution is :
- Carbon
- Manganese [IV] oxide
- Lead [II] oxide
- Copper [II] oxide
Write the equation[s] for the reaction[s] to prepare lead sulphate from lead carbonate.
Define the following terms — Neutralization