Computer Science
Simplify the following expression using laws of boolean algebra:
(a.b + x + y + z).(a.b + x'.y'.z')
Boolean Algebra
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Answer
(a.b + x + y + z).(a.b + x'.y'.z')
= a.b + [(x + y + z).(x'.y'.z')] [Distributive Law]
= a.b + [(x + y + z).(x + y + z)'] [De-Morgan's Law]
= a.b + 0 [Complementary Law: (x + y + z).(x + y + z)' = 0]
= a.b
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