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Redraw the circuit of Question 1, putting in an ammeter to measure the current through the resistors and a voltmeter to measure the potential difference across the 12 Ω resistor. What would be the readings in the ammeter and the voltmeter?

Current Electricity

Answer

Redraw the circuit of Question 1, putting in an ammeter to measure the current through the resistors and a voltmeter to measure the potential difference across the 12 Ω resistor. What would be the readings in the ammeter and the voltmeter? NCERT Class 10 Science CBSE Solutions.

According to Ohm's Law,

V = IR

The total resistance of the circuit is 5 Ω + 8 Ω + 12 Ω = 25 Ω.

Potential difference (V) = 6 V,

I = VR=625\dfrac{\text{V}}{\text{R}} = \dfrac{6}{25} = 0.24 A

Hence, current shown in ammeter = 0.24 A

Let potential difference across the 12 Ω resistor be V1.

V1 = 0.24 × 12 = 2.88 V

Therefore, the voltmeter reading will be 2.88 V.

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