Prove that : (log a) 2 - (log b) 2 = log . log (ab)

To prove: (log a) 2 - (log b) 2 = log . log (ab) Solving L.H.S. of the above equation, we get : ⇒ (log a) 2 - (log b) 2 ⇒ (log a + log b)(log a - log b) ⇒ log ab. log Hence, proved that (log a) 2 - (log b) 2 = log . log (ab)

Mathematics

Prove that :
(log a)² - (log b)² = log $\Big(\dfrac{a}{b}\Big)$ . log (ab)

Logarithms

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Answer

To prove:

(log a)² - (log b)² = log $\Big(\dfrac{a}{b}\Big)$ . log (ab)

Solving L.H.S. of the above equation, we get :

⇒ (log a)² - (log b)²

⇒ (log a + log b)(log a - log b)

⇒ log ab. log $\Big(\dfrac{a}{b}\Big)$

Hence, proved that (log a)² - (log b)² = log $\Big(\dfrac{a}{b}\Big)$ . log (ab)

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Mathematics

Prove that :
(log a)² - (log b)² = log $\Big(\dfrac{a}{b}\Big)$ . log (ab)

Logarithms

Answer

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Prove that :(log a)2 - (log b)2 = log (ab)\Big(\dfrac{a}{b}\Big)(ba​). log (ab)

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