Mathematics

Points (3, 0) and (-1, 0) are invariant points under reflection in the line L1; points (0, -3) and (0, 1) are invariant points on reflection in line L2.

(i) Name and write equations for the lines L1 and L2.

(ii) Write down the images of points P(3, 4) and Q(-5, -2) on reflection in L1. Name the images as P' and Q' respectively.

(iii) Write down the images of P and Q on reflection in L2. Name the images as P" and Q" respectively.

(iv) State or describe a single transformation that maps P' onto P".

Reflection

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Answer

(i) We know that every point in a line is invariant under the reflection in the same line.

Since, the points (3, 0) and (-1, 0) lie on the x-axis.

So, points (3, 0) and (-1, 0) are invariant under reflection in x-axis.

So, L1 = x axis.

Since, the points (0, -3) and (0, 1) lie on the y-axis.

So, points (0, -3) and (0, 1) are invariant under reflection in y-axis.

So, L2 = y axis.

Hence, L1 = x-axis whose equation is y = 0 and L2 = y-axis whose equation is x = 0.

(ii) Line L1 is x axis.

Reflection in x-axis is given by,

Mx(x, y) = (x, -y)

∴ Image on reflection of P(3, 4) in L1 (x-axis) = P'(3, -4)

Similarly, image on reflection of Q(-5, -2) in L1 (x-axis) = Q'(-5, 2)

Hence, co-ordinates of P' = (3, -4) and Q' = (-5, 2).

(iii) Line L2 is y axis.

Reflection in y-axis is given by,

My(x, y) = (-x, y)

∴ Image on reflection of P(3, 4) in L2 (y-axis) = P''(-3, 4)

Similarly, image on reflection of Q(-5, -2) in L2 (y-axis) = Q''(5, -2)

Hence, co-ordinates of P" = (-3, 4) and Q" = (5, -2).

(iv) P' = (3, -4) and P" = (-3, 4)

P'(3, -4) ⇒ P"(-3, 4)

Since sign of both abscissa and ordinate is changed, this transformation is possible on reflection in origin.

Hence, reflection in origin maps P' onto P".

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