Mathematics
P is a point on bisector of angle A of △ABC. Then:
P is equidistant from the vertices B and C
PA = PC
PA = PB
P is equidistant from sides AB and AC of the △ABC.
Locus
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Answer
We know that,
The locus of a point equidistant from two intersecting lines is the bisector of the angles between the lines.
Given,
P is a point on bisector of angle A of △ABC.
∴ P is equidistant from sides AB and AC of the △ABC.
Hence, Option 4 is the correct option.
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