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Chemistry

Nitrogen and hydrogen react to form ammonia.

N2 (g) + 3H2 (g) ⟶ 2NH3 (g)

If 1000 g of H2 react with 2000 g of N2:

(a) Will any of the two reactants remain unreacted? If yes, which one and what will be it's mass?

(b) Calculate the mass of ammonia (NH3) that will be formed?

Mole Concept

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Answer

N2+3H2⟶2NH32(14)6(1)2[14+3(1)]28g6g34 g\begin{matrix} \text{N}2 & + & 3\text{H}2& \longrightarrow & 2\text{NH}_3 \ 2(14) && 6(1) & & 2[14 + 3(1)] \ 28 \text{g} & & 6 \text{g} & & 34 \text{ g} \ \end{matrix}

(a) 28 g of nitrogen requires 6 g of hydrogen

∴ 2000 g of nitrogen requires 628\dfrac{6}{28} x 2000

= 428.57 g of hydrogen.

So mass of hydrogen left unreacted = 1000 - 428.57 = 571.42 g

571.42 g of hydrogen is left unreacted.

(b) 28 g of nitrogen forms 34 g NH3

∴ 2000 g of nitrogen forms 3428\dfrac{34}{28} x 2000

= 2428.57 g of NH3

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